Here is an interesting question that could test your knowledge and understanding of probabilities. If you fail to get the correct answer the first time, or even after considering it for a long time, do not worry, you are in esteemed company. Most get the answer wrong when they first attempt the problem, so take time to think about it.
You are in a casino playing in a tournament and during the break, a dealer takes out 3 cards from the deck -- two Deuces and one Ace. He then mixes the 3 cards, places them in a row, and takes a look at them (without showing anyone else) so he knows which card is the Ace and which are the 2 deuces.
He then says he will give you $10,000 if you can choose the Ace. You point to one of the cards (it does not matter which one) but before flipping it over, the dealer flips over one of the other 2 cards that you did NOT choose showing a deuce. Remember that the dealer knows what the cards are, so he always shows you a deuce, never an Ace. The dealer then offers you the chance to stick with your original card, or switch to the card you did not pick originally and that the dealer did not reveal to be a deuce.
So for example, you choose card B, the dealer flips over card C showing a deuce and says you can stick with card B, or switch to card A.
What gives you the best chance of winning the $10,000?
- It makes no difference if you switch cards. As there are 2 remaining cards (1 Ace and 1 Deuce) you have a 50% chance of drawing the Ace either way.
- Stick with your original card. You have a much better chance with it than with the other card.
- Switch cards. Your odds improve if you dump your original card for the other.
- There is not enough information to answer the question.